What is the integral from 0 to 3 of integral from 0 to y of e^{-y^2} ?

The integral from 0 to 3 of integral from 0 to y of e^{-y^2} is (e^9-1)/(2e^9)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 3 of integral from 0 to y of e^{-y^2}

\int_{0}^{3} \int_{0}^{y} e^{- y^{2}} d x d y

\frac{e ^{9} - 1}{2 e ^{9}}

Decimal Notation

0.49993 \dots

Solution steps

\int_{0}^{3} \int_{0}^{y} e^{- y^{2}} d x d y

\int_{0}^{y} e^{- y^{2}} d x = y e^{- y^{2}}

= \int_{0}^{3} y e^{- y^{2}} d y

\int_{0}^{3} y e^{- y^{2}} d y = \frac{e ^{9} - 1}{2 e ^{9}}

= \frac{e ^{9} - 1}{2 e ^{9}}

\int x^{2} + 3 x + C d x

n = 0 \sum \infty n (\frac{6}{7})^{n}

\int 2000 (x - 4) e^{x^{2} - 8 x} d x

2 x^{2} - 4

f (x) = x^{3} + 2

What is the integral from 0 to 3 of integral from 0 to y of e^{-y^2} ?
The integral from 0 to 3 of integral from 0 to y of e^{-y^2} is (e^9-1)/(2e^9)