What is area y=e^x,y=e^{-3x},x=ln(3) ?

The answer to area y=e^x,y=e^{-3x},x=ln(3) is 136/81

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area y=e^x,y=e^{-3x},x=ln(3)

area

y = e^{x}, y = e^{- 3 x}, x = ln (3)

\frac{136}{81}

Decimal Notation

1.67901 \dots

Solution steps

Apply the area formula:

\int_{0}^{l n (3)} e^{x} - e^{- 3 x} d x

Solve

\int_{0}^{l n (3)} e^{x} - e^{- 3 x} d x : \frac{136}{81}

The area is:

= \frac{136}{81}

\frac{\partial}{\partial x} (x y (x - 2) (y - 3))

\frac{d}{d x} ((1 - 2 x)^{2})

f (x) = x ln (x)

\int 3 x^{2} + 4 d x

\int 1 ln (x^{2} - 1) d x

What is area y=e^x,y=e^{-3x},x=ln(3) ?
The answer to area y=e^x,y=e^{-3x},x=ln(3) is 136/81