What is the derivative of (3x-1^5) ?

The derivative of (3x-1^5) is 15(3x-1)^4

What is the first derivative of (3x-1^5) ?

The first derivative of (3x-1^5) is 15(3x-1)^4

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\frac{d}{d x} ((3 x - 1)^{5})

15 (3 x - 1)^{4}

Solution steps

\frac{d}{d x} ((3 x - 1)^{5})

Apply the chain rule:

5 (3 x - 1)^{4} \frac{d}{d x} (3 x - 1)

= 5 (3 x - 1)^{4} \frac{d}{d x} (3 x - 1)

\frac{d}{d x} (3 x - 1) = 3

= 5 (3 x - 1)^{4} \cdot 3

Simplify

= 15 (3 x - 1)^{4}

\int \frac{1}{x ^{2} y} d y

- x^{3} + 9 x^{2} - 6 x + 9

sin (2 x) cos (3 x)

\int x^{2} e^{x} cos (x) d x

\int 2 x cos (x^{2}) d x

What is the derivative of (3x-1^5) ?
The derivative of (3x-1^5) is 15(3x-1)^4
What is the first derivative of (3x-1^5) ?
The first derivative of (3x-1^5) is 15(3x-1)^4