What is area f(x)=0.2x^2+10,g(x)=x,x=-7,x=2 ?

The answer to area f(x)=0.2x^2+10,g(x)=x,x=-7,x=2 is 135.9

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area f(x)=0.2x^2+10,g(x)=x,x=-7,x=2

area

f (x) = 0.2 x^{2} + 10, g (x) = x, x = - 7, x = 2

135.9

Solution steps

Apply the area formula:

\int_{- 7}^{2} 0.2 x^{2} + 10 - x d x

Solve

\int_{- 7}^{2} 0.2 x^{2} + 10 - x d x : 135.9

The area is:

= 135.9

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(e^{x + 2})^{^{'}}

\frac{d}{d z} (x^{y^{z}})

What is area f(x)=0.2x^2+10,g(x)=x,x=-7,x=2 ?
The answer to area f(x)=0.2x^2+10,g(x)=x,x=-7,x=2 is 135.9