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Popular >

derivative of 0.001x^3+4x+1458

Solution

derivative of

0.001 x^{3} + 4 x + 1458

Solution

0.003 x^{2} + 4

Solution steps

\frac{d}{d x} (0.001 x^{3} + 4 x + 1458)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (0.001 x^{3}) + \frac{d}{d x} (4 x) + \frac{d}{d x} (1458)

\frac{d}{d x} (0.001 x^{3}) = 0.003 x^{2}

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (1458) = 0

= 0.003 x^{2} + 4 + 0

Simplify

= 0.003 x^{2} + 4

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Frequently Asked Questions (FAQ)

What is the derivative of 0.001x^3+4x+1458 ?
The derivative of 0.001x^3+4x+1458 is 0.003x^2+4
What is the first derivative of 0.001x^3+4x+1458 ?
The first derivative of 0.001x^3+4x+1458 is 0.003x^2+4