What is the d/(dt)(sin(t)+cos(t)) ?

The d/(dt)(sin(t)+cos(t)) is cos(t)-sin(t)

What is the first d/(dt)(sin(t)+cos(t)) ?

The first d/(dt)(sin(t)+cos(t)) is cos(t)-sin(t)

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\frac{d}{d t} (sin (t) + cos (t))

cos (t) - sin (t)

Solution steps

\frac{d}{d t} (sin (t) + cos (t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (sin (t)) + \frac{d}{d t} (cos (t))

\frac{d}{d t} (sin (t)) = cos (t)

\frac{d}{d t} (cos (t)) = - sin (t)

= cos (t) - sin (t)

\frac{d y}{d x} + 3 y = 5

\frac{\partial}{\partial x} (\frac{1}{y - 3 x})

y = x^{3}, (- 1, 2)

\frac{\partial}{\partial x} (3 + x ln (x y - 9))

y^{^{''}} + 3 y^{^{'}} + 3.25 y = 3 cos (t) - 1.5 sin (t)

What is the d/(dt)(sin(t)+cos(t)) ?
The d/(dt)(sin(t)+cos(t)) is cos(t)-sin(t)
What is the first d/(dt)(sin(t)+cos(t)) ?
The first d/(dt)(sin(t)+cos(t)) is cos(t)-sin(t)