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Popular >

tangent of y=x^3-x,(1,0)

Solution

tangent of

y = x^{3} - x, (1, 0)

Solution

y = 2 x - 2

Solution steps

Find the slope of

y = x^{3} - x : \frac{d y}{d x} = 3 x^{2} - 1

Compute the slope of

y = x^{3} - x

at

(1, 0) : m = 2

Find the line with slope m=

2

and passing through

(1, 0) : y = 2 x - 2

y = 2 x - 2

Popular Examples

derivative of x/(x^2-15)

\frac{d}{d x} (\frac{x}{x ^{2} - 15})

integral of 9/((x-2)(x^2+4))

\int \frac{9}{( x - 2 ) ( x ^{2} + 4 )} d x

slope of (4.4)(5.9)slope

(4.4) (5.9)

y^{''}-y^'+16y=4sin(4t)

y^{^{''}} - y^{^{'}} + 16 y = 4 sin (4 t)

(\partial)/(\partial x)(9xsin(y-z))

\frac{\partial}{\partial x} (9 x sin (y - z))

Frequently Asked Questions (FAQ)

What is the tangent of y=x^3-x,(1,0) ?
The tangent of y=x^3-x,(1,0) is y=2x-2