What is the derivative of y=arctan(1)-x^1+x ?

The derivative of y=arctan(1)-x^1+x is 0

What is the first derivative of y=arctan(1)-x^1+x ?

The first derivative of y=arctan(1)-x^1+x is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = arctan (1) - x^{1} + x

0

Solution steps

\frac{d}{d x} (arctan (1) - x^{1} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (arctan (1)) - \frac{d}{d x} (x^{1}) + \frac{d x}{d x}

\frac{d}{d x} (arctan (1)) = 0

\frac{d}{d x} (x^{1}) = 1

\frac{d x}{d x} = 1

= 0 - 1 + 1

Simplify

= 0

\int_{2}^{t} \frac{1}{( 5 x ^{5} )} d x

\int \frac{tan ^{3} ( ln ( x ) )}{6 x} d x

\int \frac{1}{P - P ^{2}} d P

x \to 0 lim (\frac{2}{x})

x \to 0 lim (x sin (\frac{8 π}{x}))

What is the derivative of y=arctan(1)-x^1+x ?
The derivative of y=arctan(1)-x^1+x is 0
What is the first derivative of y=arctan(1)-x^1+x ?
The first derivative of y=arctan(1)-x^1+x is 0