What is the tangent of f(x)=(2x)/(x^2-7),(3,3) ?

The tangent of f(x)=(2x)/(x^2-7),(3,3) is y=-8x+27

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=(2x)/(x^2-7),(3,3)

tangent of

f (x) = \frac{2 x}{x ^{2} - 7}, (3, 3)

y = - 8 x + 27

Solution steps

Find the slope of

f (x) = \frac{2 x}{x ^{2} - 7} : \frac{df ( x )}{d x} = \frac{2 ( - x ^{2} - 7 )}{( x ^{2} - 7 ) ^{2}}

Compute the slope of

f (x) = \frac{2 x}{x ^{2} - 7}

(3, 3) : m = - 8

Find the line with slope m=

- 8

and passing through

(3, 3) : y = - 8 x + 27

y = - 8 x + 27

\frac{d}{d x} (- 11 e^{x} sin (2 x) - 2 e^{x} cos (2 x))

y = x^{2} + 8, (4, 24)

(x^{2} + 1) y^{^{'}} + 9 x (y - 1) = 0

\int \frac{1}{csc ( x ) - 1} d x

x \to 0 lim (\frac{5 e ^{x} - 5}{x})

What is the tangent of f(x)=(2x)/(x^2-7),(3,3) ?
The tangent of f(x)=(2x)/(x^2-7),(3,3) is y=-8x+27