What is the solution for (x^2+1)y^'+9x(y-1)=0 ?

The solution for (x^2+1)y^'+9x(y-1)=0 is y=(c_{1})/((x^2+1)^{9/2)}+1

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(x^2+1)y^'+9x(y-1)=0

(x^{2} + 1) y^{^{'}} + 9 x (y - 1) = 0

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{9}{2}}} + 1

Solution steps

(x^{2} + 1) y^{'} (x) + 9 x (y - 1) = 0

Solve separable ODE:

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{9}{2}}} + 1

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{9}{2}}} + 1

\int \frac{1}{csc ( x ) - 1} d x

x \to 0 lim (\frac{5 e ^{x} - 5}{x})

\int (cos (x))^{4} d x

\int_{0}^{1} \frac{3}{4 - x ^{2}} d x

f (x) = \frac{x - 3}{x + 4}

What is the solution for (x^2+1)y^'+9x(y-1)=0 ?
The solution for (x^2+1)y^'+9x(y-1)=0 is y=(c_{1})/((x^2+1)^{9/2)}+1