What is the sum from n=0 to infinity of (n+2)/(n+1) ?

The sum from n=0 to infinity of (n+2)/(n+1) is diverges

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sum from n=0 to infinity of (n+2)/(n+1)

n = 0 \sum \infty \frac{n + 2}{n + 1}

diverges

Solution steps

n = 0 \sum \infty \frac{n + 2}{n + 1}

Apply Series Divergence Test:

diverges

= diverges

\frac{1}{4} x^{2} - 1, 0, 2, 8

\int_{0}^{2} \frac{1}{( x - 1 ) ^{2}} d x

y = 2 sin (x)

\frac{\partial}{\partial x} (x + y)

f (x) = - x^{3} + 4 x - 2, at x = - 2

What is the sum from n=0 to infinity of (n+2)/(n+1) ?
The sum from n=0 to infinity of (n+2)/(n+1) is diverges