What is the solution for x(dy}{dx}+2y=\frac{sin(x))/x ?

The solution for x(dy}{dx}+2y=\frac{sin(x))/x is y=-(cos(x))/(x^2)+(c_{1})/(x^2)

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x(dy}{dx}+2y=\frac{sin(x))/x

x \frac{d y}{d x} + 2 y = \frac{sin ( x )}{x}

y = - \frac{cos ( x )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

Solution steps

x \frac{d y}{d x} + 2 y = \frac{sin ( x )}{x}

Solve linear ODE:

y = - \frac{cos ( x )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

y = - \frac{cos ( x )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

\int cos (\frac{x}{7}) d x

2 y^{^{''}} + 3 y^{^{'}} - 2 y = 2 x - 3

y^{^{''}} - 8 y^{^{'}} + 16 y = t^{- 4} e^{4 t}

\int_{1}^{2} 5 x^{2} ln (x) d x

f (x) = 6 x^{\frac{1}{2}}

What is the solution for x(dy}{dx}+2y=\frac{sin(x))/x ?
The solution for x(dy}{dx}+2y=\frac{sin(x))/x is y=-(cos(x))/(x^2)+(c_{1})/(x^2)