What is the tangent of-5x^2+4 ?

The tangent of-5x^2+4 is y=-10a_{0}x+5a_{0}^2+4

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tangent of-5x^2+4

tangent of

- 5 x^{2} + 4

y = - 10 a_{0} x + 5 a_{0}^{2} + 4

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 5 a_{0}^{2} + 4)

Find the slope of

y = - 5 x^{2} + 4 : \frac{d y}{d x} = - 10 x

Compute the slope of

y = - 5 x^{2} + 4

x = a_{0} : m = - 10 a_{0}

Find the line with slope m=

- 10 a_{0}

and passing through

(a_{0}, - 5 a_{0}^{2} + 4) : y = - 10 a_{0} x + 5 a_{0}^{2} + 4

y = - 10 a_{0} x + 5 a_{0}^{2} + 4

\frac{d}{d x} (6 - 5 cos (\frac{π x}{15}))

\int \frac{x ^{4} + 4}{x ^{4}} d x

\frac{d}{d x} (x - 1 + x + 1)

b \to 7 lim (6 b + 31)