What is the solution for (dy)/(dx)=(2x(y-2))/(x^2+1),y(0)=4 ?

The solution for (dy)/(dx)=(2x(y-2))/(x^2+1),y(0)=4 is y=2x^2+4

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(dy)/(dx)=(2x(y-2))/(x^2+1),y(0)=4

\frac{d y}{d x} = \frac{2 x ( y - 2 )}{x ^{2} + 1}, y (0) = 4

y = 2 x^{2} + 4

Solution steps

\frac{d y}{d x} = \frac{2 x ( y - 2 )}{x ^{2} + 1}

Solve separable ODE:

y = 2 x^{2} + 4

y = 2 x^{2} + 4

y^{^{''''}} - 81 y = 0

\frac{\partial}{\partial x} (- e^{- x})

\frac{x ^{2} - 9 x + 8}{x ^{2} + 9}

n = 1 \sum \infty \frac{8}{n} - \frac{8}{n + 1}

\int \frac{6 x - 11}{( x - 1 ) ^{2}} d x

What is the solution for (dy)/(dx)=(2x(y-2))/(x^2+1),y(0)=4 ?
The solution for (dy)/(dx)=(2x(y-2))/(x^2+1),y(0)=4 is y=2x^2+4