What is the derivative of 6/((s+3)^2) ?

The derivative of 6/((s+3)^2) is -(12)/((s+3)^3)

What is the first derivative of 6/((s+3)^2) ?

The first derivative of 6/((s+3)^2) is -(12)/((s+3)^3)

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derivative of

\frac{6}{( s + 3 ) ^{2}}

- \frac{12}{( s + 3 ) ^{3}}

Solution steps

\frac{d}{d s} (\frac{6}{( s + 3 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d s} (\frac{1}{( s + 3 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 6 \frac{d}{d s} ((s + 3)^{- 2})

Apply the chain rule:

- \frac{2}{( s + 3 ) ^{3}} \frac{d}{d s} (s + 3)

= - \frac{2}{( s + 3 ) ^{3}} \frac{d}{d s} (s + 3)

\frac{d}{d s} (s + 3) = 1

= 6 (- \frac{2}{( s + 3 ) ^{3}} \cdot 1)

Simplify

6 (- \frac{2}{( s + 3 ) ^{3}} \cdot 1) : - \frac{12}{( s + 3 ) ^{3}}

= - \frac{12}{( s + 3 ) ^{3}}

\int (1 - 3 x)^{\frac{1}{2}} d x

x^{2}

\frac{2 s + 1}{s ^{2}}

x y^{^{'}} + y = x y^{3}

n = 0 \sum \infty (\frac{3}{8})^{\frac{n}{2}}

What is the derivative of 6/((s+3)^2) ?
The derivative of 6/((s+3)^2) is -(12)/((s+3)^3)
What is the first derivative of 6/((s+3)^2) ?
The first derivative of 6/((s+3)^2) is -(12)/((s+3)^3)