What is the derivative of sqrt(x+1)-x^2+x ?

The derivative of sqrt(x+1)-x^2+x is 1/(2sqrt(x+1))-2x+1

What is the first derivative of sqrt(x+1)-x^2+x ?

The first derivative of sqrt(x+1)-x^2+x is 1/(2sqrt(x+1))-2x+1

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\frac{d}{d x} (x + 1 - x^{2} + x)

\frac{1}{2 x + 1} - 2 x + 1

Solution steps

\frac{d}{d x} (x + 1 - x^{2} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x + 1) - \frac{d}{d x} (x^{2}) + \frac{d x}{d x}

\frac{d}{d x} (x + 1) = \frac{1}{2 x + 1}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

= \frac{1}{2 x + 1} - 2 x + 1

\int sin (lo g_{10} (x)) d x

\frac{x ^{2} - 1}{( 2 x - 5 ) ^{2}}

\frac{\partial}{\partial x} (ln (1 - 2 x))

\frac{d}{d x} (4 cos (sin (3 x)))

y^{^{'''}} + y^{^{'}} = t^{2}

What is the derivative of sqrt(x+1)-x^2+x ?
The derivative of sqrt(x+1)-x^2+x is 1/(2sqrt(x+1))-2x+1
What is the first derivative of sqrt(x+1)-x^2+x ?
The first derivative of sqrt(x+1)-x^2+x is 1/(2sqrt(x+1))-2x+1