What is the derivative of ln(3x^2+4) ?

The derivative of ln(3x^2+4) is (6x)/(3x^2+4)

What is the first derivative of ln(3x^2+4) ?

The first derivative of ln(3x^2+4) is (6x)/(3x^2+4)

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\frac{d}{d x} (ln (3 x^{2} + 4))

\frac{6 x}{3 x ^{2} + 4}

Solution steps

\frac{d}{d x} (ln (3 x^{2} + 4))

Apply the chain rule:

\frac{1}{3 x ^{2} + 4} \frac{d}{d x} (3 x^{2} + 4)

= \frac{1}{3 x ^{2} + 4} \frac{d}{d x} (3 x^{2} + 4)

\frac{d}{d x} (3 x^{2} + 4) = 6 x

= \frac{1}{3 x ^{2} + 4} \cdot 6 x

Simplify

\frac{1}{3 x ^{2} + 4} \cdot 6 x : \frac{6 x}{3 x ^{2} + 4}

= \frac{6 x}{3 x ^{2} + 4}

x \to - 5 lim (\frac{x ^{2} - 8}{5 - x})

\frac{d}{d x} (24 x^{\frac{3}{2}})

\frac{d y}{d x} = 5 x (x - 3)

y^{^{'}} - y = 7 t e^{2 t}, y (0) = 1

e^{x} - 1

What is the derivative of ln(3x^2+4) ?
The derivative of ln(3x^2+4) is (6x)/(3x^2+4)
What is the first derivative of ln(3x^2+4) ?
The first derivative of ln(3x^2+4) is (6x)/(3x^2+4)