What is the tangent of f(x)= 1/(3+2x),(1, 1/5) ?

The tangent of f(x)= 1/(3+2x),(1, 1/5) is y=-2/25 x+7/25

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tangent of f(x)= 1/(3+2x),(1, 1/5)

tangent of

f (x) = \frac{1}{3 + 2 x}, (1, \frac{1}{5})

y = - \frac{2}{25} x + \frac{7}{25}

Solution steps

Find the slope of

f (x) = \frac{1}{3 + 2 x} : \frac{df ( x )}{d x} = - \frac{2}{( 3 + 2 x ) ^{2}}

Compute the slope of

f (x) = \frac{1}{3 + 2 x}

(1, \frac{1}{5}) : m = - \frac{2}{25}

Find the line with slope m=

- \frac{2}{25}

and passing through

(1, \frac{1}{5}) : y = - \frac{2}{25} x + \frac{7}{25}

y = - \frac{2}{25} x + \frac{7}{25}

\frac{d}{d x} (\frac{c x + b}{4 x + d})

\frac{d ^{2}}{d x ^{2}} (cos (x^{2}))

\int - x^{5} sin (x) d x

x \to 0 lim (500)

\frac{\partial}{\partial x} ((4 x^{3} y^{4} + 9)^{2})

What is the tangent of f(x)= 1/(3+2x),(1, 1/5) ?
The tangent of f(x)= 1/(3+2x),(1, 1/5) is y=-2/25 x+7/25