What is area e^{3x}+1,y=0,x=0,x=0.6 ?

The answer to area e^{3x}+1,y=0,x=0,x=0.6 is 2.28321…

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area e^{3x}+1,y=0,x=0,x=0.6

area

e^{3 x} + 1, y = 0, x = 0, x = 0.6

2.28321 \dots

Solution steps

Apply the area formula:

\int_{0}^{0.6} e^{3 x} + 1 d x

Solve

\int_{0}^{0.6} e^{3 x} + 1 d x : 2.28321 \dots

The area is:

= 2.28321 \dots

y^{^{''}} + 14 y^{^{'}} + 49 y = 0, y (0) = 0, y^{^{'}} (0) = 1

\frac{\partial}{\partial x} ((2 x + 2 y)^{\frac{1}{2}})

\int \frac{3 ^{x}}{ln ( 3 )} d x

\frac{d}{d x} (sin (2 x^{3}))

6 x y^{^{'}} - 2 y = \frac{( - x ^{2} )}{y ^{5}}

What is area e^{3x}+1,y=0,x=0,x=0.6 ?
The answer to area e^{3x}+1,y=0,x=0,x=0.6 is 2.28321…