What is the derivative of (2x^4+3x^2-1/(x^2)) ?

The derivative of (2x^4+3x^2-1/(x^2)) is (2(2x^4+1))/(x^3)

What is the first derivative of (2x^4+3x^2-1/(x^2)) ?

The first derivative of (2x^4+3x^2-1/(x^2)) is (2(2x^4+1))/(x^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{2 x ^{4} + 3 x ^{2} - 1}{x ^{2}})

\frac{2 ( 2 x ^{4} + 1 )}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{2 x ^{4} + 3 x ^{2} - 1}{x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x ^{4} + 3 x ^{2} - 1 ) x ^{2} - \frac{d}{d x} ( x ^{2} ) ( 2 x ^{4} + 3 x ^{2} - 1 )}{( x ^{2} ) ^{2}}

\frac{d}{d x} (2 x^{4} + 3 x^{2} - 1) = 8 x^{3} + 6 x

\frac{d}{d x} (x^{2}) = 2 x

= \frac{( 8 x ^{3} + 6 x ) x ^{2} - 2 x ( 2 x ^{4} + 3 x ^{2} - 1 )}{( x ^{2} ) ^{2}}

Simplify

\frac{( 8 x ^{3} + 6 x ) x ^{2} - 2 x ( 2 x ^{4} + 3 x ^{2} - 1 )}{( x ^{2} ) ^{2}} : \frac{2 ( 2 x ^{4} + 1 )}{x ^{3}}

= \frac{2 ( 2 x ^{4} + 1 )}{x ^{3}}

x \to \frac{π}{2} lim (\frac{π}{2} - x)

\frac{2}{7 x ^{2}}

\int \frac{( x ^{2} + 2 x + 3 )}{( x ^{3} + 3 x ^{2} + 9 x )} d x

\frac{d}{d y} (3 x y)

x \to 0 lim ((1 - 3 x)^{\frac{3}{x}})

What is the derivative of (2x^4+3x^2-1/(x^2)) ?
The derivative of (2x^4+3x^2-1/(x^2)) is (2(2x^4+1))/(x^3)
What is the first derivative of (2x^4+3x^2-1/(x^2)) ?
The first derivative of (2x^4+3x^2-1/(x^2)) is (2(2x^4+1))/(x^3)