What is the derivative of 9*sqrt(t+1) ?

The derivative of 9*sqrt(t+1) is 9/(2sqrt(t+1))

What is the first derivative of 9*sqrt(t+1) ?

The first derivative of 9*sqrt(t+1) is 9/(2sqrt(t+1))

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derivative of

9 \cdot t + 1

\frac{9}{2 t + 1}

Solution steps

\frac{d}{d t} (9 t + 1)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d t} (t + 1)

Apply the chain rule:

\frac{1}{2 t + 1} \frac{d}{d t} (t + 1)

= \frac{1}{2 t + 1} \frac{d}{d t} (t + 1)

\frac{d}{d t} (t + 1) = 1

= 9 \cdot \frac{1}{2 t + 1} \cdot 1

Simplify

9 \cdot \frac{1}{2 t + 1} \cdot 1 : \frac{9}{2 t + 1}

= \frac{9}{2 t + 1}

\frac{d}{d x} (x e^{- \frac{x}{4}})

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\frac{d}{d x} (e^{5 x + 1} arccsch (x + 1))

n = 1 \sum \infty \frac{2}{3 ^{2 n}}

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What is the derivative of 9*sqrt(t+1) ?
The derivative of 9*sqrt(t+1) is 9/(2sqrt(t+1))
What is the first derivative of 9*sqrt(t+1) ?
The first derivative of 9*sqrt(t+1) is 9/(2sqrt(t+1))