What is the derivative of 3/(x^4) ?

The derivative of 3/(x^4) is -(12)/(x^5)

What is the first derivative of 3/(x^4) ?

The first derivative of 3/(x^4) is -(12)/(x^5)

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\frac{d}{d x} (\frac{3}{x ^{4}})

- \frac{12}{x ^{5}}

Solution steps

\frac{d}{d x} (\frac{3}{x ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{x ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} (x^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 (- 4 x^{- 4 - 1})

Simplify

3 (- 4 x^{- 4 - 1}) : - \frac{12}{x ^{5}}

= - \frac{12}{x ^{5}}

\frac{\partial}{\partial x} (7 - x^{5} - y^{3})

\frac{\partial}{\partial u} (x^{5} v^{2} + 2 y^{3} u - 3)

\frac{\partial}{\partial x} (61 - x^{2} - 3 y^{2})

\int_{2}^{5} x^{2} d x

x \to 0 + lim (7 sin (x) ln (x))

What is the derivative of 3/(x^4) ?
The derivative of 3/(x^4) is -(12)/(x^5)
What is the first derivative of 3/(x^4) ?
The first derivative of 3/(x^4) is -(12)/(x^5)