What is the integral from 0 to 5 of 2/(x^2) ?

The integral from 0 to 5 of 2/(x^2) is diverges

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integral from 0 to 5 of 2/(x^2)

\int_{0}^{5} \frac{2}{x ^{2}} d x

diverges

Solution steps

\int_{0}^{5} \frac{2}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{5} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{0}^{5}

= 2 [- \frac{1}{x}]_{0}^{5}

Compute the boundaries:

diverges

= diverges

\frac{d y}{d t} = - \frac{y}{t} - 7

\frac{d}{d x} (\frac{2}{( 1 - x ) ^{3}})

\frac{\partial}{\partial x} (z \cdot lo g_{e} (x^{2} + y^{2}))

(6 x^{4} - 9 x^{2} + 8)^{4}

x \to - 1 - lim (x^{2} + 1)

What is the integral from 0 to 5 of 2/(x^2) ?
The integral from 0 to 5 of 2/(x^2) is diverges