What is (\partial)/(\partial y)(10xzsin(y)) ?

The answer to (\partial)/(\partial y)(10xzsin(y)) is 10xzcos(y)

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(\partial)/(\partial y)(10xzsin(y))

\frac{\partial}{\partial y} (10 x z sin (y))

10 x z cos (y)

Solution steps

\frac{\partial}{\partial y} (10 x z sin (y))

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 10 x z \frac{\partial}{\partial y} (sin (y))

Apply the common derivative:

\frac{\partial}{\partial y} (sin (y)) = cos (y)

= 10 x z cos (y)

\int \frac{1}{( 121 + x ^{2} ) ^{\frac{3}{2}}} d x

y^{^{'}} = 7 x y

e^{0.75 t} y^{^{'}} + 0.75 y e^{0.75 t} = - 0.00003 e^{0.75 t}

f (x) = - 3 cos (x) + 2 sin (x)

\frac{\partial}{\partial x} (7 x^{6} y^{4} + 8 x^{5} y^{7})

What is (\partial)/(\partial y)(10xzsin(y)) ?
The answer to (\partial)/(\partial y)(10xzsin(y)) is 10xzcos(y)