en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 2 of (x^3+x^2-8x-12)/(x^4+4x^3+5x^2+4x+4)

Solution

x \to 2 lim (\frac{x ^{3} + x ^{2} - 8 x - 12}{x ^{4} + 4 x ^{3} + 5 x ^{2} + 4 x + 4})

Solution

- \frac{1}{5}

+1

Decimal Notation

- 0.2

Solution steps

x \to 2 lim (\frac{x ^{3} + x ^{2} - 8 x - 12}{x ^{4} + 4 x ^{3} + 5 x ^{2} + 4 x + 4})

Plug in the value

x = 2

= \frac{2 ^{3} + 2 ^{2} - 8 \cdot 2 - 12}{2 ^{4} + 4 \cdot 2 ^{3} + 5 \cdot 2 ^{2} + 4 \cdot 2 + 4}

Simplify

\frac{2 ^{3} + 2 ^{2} - 8 \cdot 2 - 12}{2 ^{4} + 4 \cdot 2 ^{3} + 5 \cdot 2 ^{2} + 4 \cdot 2 + 4} : - \frac{1}{5}

= - \frac{1}{5}

Popular Examples

(\partial)/(\partial x)(z^3-xy+yz+y^3-2)

\frac{\partial}{\partial x} (z^{3} - x y + yz + y^{3} - 2)

inverse oflaplace 4/([s(s^2+4)])inverse laplace

\frac{4}{[ s ( s ^{2} + 4 ) ]}

y^'=((t^4+y^4))/(ty^3)

y^{^{'}} = \frac{( t ^{4} + y ^{4} )}{t y ^{3}}

integral of (3-x)/(x^2-1)

\int \frac{3 - x}{x ^{2} - 1} d x

limit as x approaches-1-of (x-2)/(x^2-1)

x \to - 1 - lim (\frac{x - 2}{x ^{2} - 1})

Frequently Asked Questions (FAQ)

What is the limit as x approaches 2 of (x^3+x^2-8x-12)/(x^4+4x^3+5x^2+4x+4) ?
The limit as x approaches 2 of (x^3+x^2-8x-12)/(x^4+4x^3+5x^2+4x+4) is -1/5