What is the integral of (x^5-3x)/(x^4) ?

The integral of (x^5-3x)/(x^4) is (x^2)/2+3/(2x^2)+C

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integral of (x^5-3x)/(x^4)

\int \frac{x ^{5} - 3 x}{x ^{4}} d x

\frac{x ^{2}}{2} + \frac{3}{2 x ^{2}} + C

Solution steps

\int \frac{x ^{5} - 3 x}{x ^{4}} d x

Expand

\frac{x ^{5} - 3 x}{x ^{4}} : x - \frac{3}{x ^{3}}

= \int x - \frac{3}{x ^{3}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x d x - \int \frac{3}{x ^{3}} d x

\int x d x = \frac{x ^{2}}{2}

\int \frac{3}{x ^{3}} d x = - \frac{3}{2 x ^{2}}

= \frac{x ^{2}}{2} - (- \frac{3}{2 x ^{2}})

Simplify

= \frac{x ^{2}}{2} + \frac{3}{2 x ^{2}}

Add a constant to the solution

= \frac{x ^{2}}{2} + \frac{3}{2 x ^{2}} + C

\int 4 y + 2 x - 5 d x

y = x^{2} + 1, x = 0, x = 6

\int - 4 sin (2 x) + 3 d x

\frac{d}{d x} (\frac{6 x - 1}{4 x + 5})

\int \frac{1}{2 x + 3} d x

What is the integral of (x^5-3x)/(x^4) ?
The integral of (x^5-3x)/(x^4) is (x^2)/2+3/(2x^2)+C