What is the limit as x approaches+1 of (x^2-9)^{1/3} ?

The limit as x approaches+1 of (x^2-9)^{1/3} is 2(-1)^{1/3}

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limit as x approaches+1 of (x^2-9)^{1/3}

x \to + 1 lim ((x^{2} - 9)^{\frac{1}{3}})

2 (- 1)^{\frac{1}{3}}

Solution steps

x \to 1 lim ((x^{2} - 9)^{\frac{1}{3}})

Plug in the value

x = 1

= (1^{2} - 9)^{\frac{1}{3}}

Simplify

(1^{2} - 9)^{\frac{1}{3}} : 2 (- 1)^{\frac{1}{3}}

= 2 (- 1)^{\frac{1}{3}}

\frac{d ^{2}}{d x ^{2}} (\frac{ln ( x )}{x})

\frac{d}{d x} (2 + e^{x})

\frac{d y}{d t} = \frac{( t e ^{t} )}{y 1 + y ^{2}}

\int \frac{e ^{3 x}}{9 + e ^{6 x}} d x

x \to 3 lim (1 0^{x^{2} - 4 x})

What is the limit as x approaches+1 of (x^2-9)^{1/3} ?
The limit as x approaches+1 of (x^2-9)^{1/3} is 2(-1)^{1/3}