What is the derivative of f(x)=\sqrt[3]{x+2} ?

The derivative of f(x)=\sqrt[3]{x+2} is 1/(3(x+2)^{2/3)}

What is the first derivative of f(x)=\sqrt[3]{x+2} ?

The first derivative of f(x)=\sqrt[3]{x+2} is 1/(3(x+2)^{2/3)}

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derivative of

\frac{1}{3 ( x + 2 ) ^{\frac{2}{3}}}

Solution steps

Apply the chain rule:

\frac{1}{3 ( x + 2 ) ^{\frac{2}{3}}} \frac{d}{d x} (x + 2)

= \frac{1}{3 ( x + 2 ) ^{\frac{2}{3}}} \frac{d}{d x} (x + 2)

\frac{d}{d x} (x + 2) = 1

= \frac{1}{3 ( x + 2 ) ^{\frac{2}{3}}} \cdot 1

Simplify

= \frac{1}{3 ( x + 2 ) ^{\frac{2}{3}}}

\frac{\partial}{\partial x} (ln (13 x^{2} - 10 y^{2}))

\frac{\partial}{\partial x} (x^{2} y^{3} sin (x - 2 y))

\frac{d}{d x} (\frac{2 x cos ( x ^{2} )}{sin ( x ^{2} ) + 1})

\int \frac{x}{a ^{2} - x ^{2}} d x

x \to 25 lim (x)

What is the derivative of f(x)=\sqrt[3]{x+2} ?
The derivative of f(x)=\sqrt[3]{x+2} is 1/(3(x+2)^{2/3)}
What is the first derivative of f(x)=\sqrt[3]{x+2} ?
The first derivative of f(x)=\sqrt[3]{x+2} is 1/(3(x+2)^{2/3)}