What is the solution for (x+y)(dy)/(dx)=1 ?

The solution for (x+y)(dy)/(dx)=1 is y=-\W((c_{1})/(e^{x+1)})-x-1

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(x+y)(dy)/(dx)=1

(x + y) \frac{d y}{d x} = 1

y = - W (\frac{c _{1}}{e ^{x + 1}}) - x - 1

Solution steps

(x + y) \frac{d y}{d x} = 1

Solve exact ODE:

y = - W (\frac{c _{1}}{e ^{x + 1}}) - x - 1

y = - W (\frac{c _{1}}{e ^{x + 1}}) - x - 1

n = 1 \sum \infty n^{- 1}

- x^{2} + 9, - 2 x^{2} + 18

\int \frac{2 x ^{2} + 14 x + 8}{x ^{3} + 9 x} d x

\frac{d}{d x} (- 85 + 50 ln (x))

\frac{\partial}{\partial x} (y + 1)

What is the solution for (x+y)(dy)/(dx)=1 ?
The solution for (x+y)(dy)/(dx)=1 is y=-\W((c_{1})/(e^{x+1)})-x-1