What is the solution for (dy)/(dt)=sin(t)-y ?

The solution for (dy)/(dt)=sin(t)-y is y=-(cos(t))/2+(sin(t))/2+(c_{1})/(e^t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dt)=sin(t)-y

\frac{d y}{d t} = sin (t) - y

y = - \frac{cos ( t )}{2} + \frac{sin ( t )}{2} + \frac{c _{1}}{e ^{t}}

Solution steps

\frac{d y}{d t} = sin (t) - y

Solve linear ODE:

y = - \frac{cos ( t )}{2} + \frac{sin ( t )}{2} + \frac{c _{1}}{e ^{t}}

y = - \frac{cos ( t )}{2} + \frac{sin ( t )}{2} + \frac{c _{1}}{e ^{t}}

\int \frac{- 1}{1 + e ^{x}} d x

x \to - 5 lim (2 (- \frac{3}{10}) (x) - 3)

\frac{\partial}{\partial y} (cos (x + y + z))

x \to \infty lim (\frac{x}{6})

x \to 1 lim (ln (1 - x))

What is the solution for (dy)/(dt)=sin(t)-y ?
The solution for (dy)/(dt)=sin(t)-y is y=-(cos(t))/2+(sin(t))/2+(c_{1})/(e^t)