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Popular >

y^'=3x+y,y(0)=2

Solution

y^{^{'}} = 3 x + y, y (0) = 2

Solution

y = - 3 (x + 1) + 5 e^{x}

Solution steps

y^{'} (x) = 3 x + y

Solve linear ODE:

y = - 3 (x + 1) + 5 e^{x}

y = - 3 (x + 1) + 5 e^{x}

Popular Examples

integral of sqrt(x^2+5)

\int x^{2} + 5 d x

limit as r approaches 0 of sin^2(r)

r \to 0 lim (sin^{2} (r))

derivative of (2-3x^3)^{-2}derivative of

(2 - 3 x^{3})^{- 2}

inverse oflaplace (e^{-5s})/((s-2)^4)inverse laplace

\frac{e ^{- 5 s}}{( s - 2 ) ^{4}}

integral of x^2+3x+1

\int x^{2} + 3 x + 1 d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=3x+y,y(0)=2 ?
The solution for y^'=3x+y,y(0)=2 is y=-3(x+1)+5e^x