What is the derivative of (3x+4(-3+2x)) ?

The derivative of (3x+4(-3+2x)) is 12x-1

What is the first derivative of (3x+4(-3+2x)) ?

The first derivative of (3x+4(-3+2x)) is 12x-1

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\frac{d}{d x} ((3 x + 4) (- 3 + 2 x))

12 x - 1

Solution steps

\frac{d}{d x} ((3 x + 4) (- 3 + 2 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 3 x + 4, g = - 3 + 2 x

= \frac{d}{d x} (3 x + 4) (- 3 + 2 x) + \frac{d}{d x} (- 3 + 2 x) (3 x + 4)

\frac{d}{d x} (3 x + 4) = 3

\frac{d}{d x} (- 3 + 2 x) = 2

= 3 (- 3 + 2 x) + 2 (3 x + 4)

Simplify

3 (- 3 + 2 x) + 2 (3 x + 4) : 12 x - 1

= 12 x - 1

\int (3 x + 8)^{\frac{2}{3}} d x

\frac{d}{d x} (\frac{2}{( x - 1 ) ^{2}})

\int \frac{1 - sin ( x )}{1 + sin ( x )} d x

\frac{d r}{d θ} + r tan (θ) = 5 tan (θ)

y^{^{''''}} + y^{^{''}} - 6 y = 0

What is the derivative of (3x+4(-3+2x)) ?
The derivative of (3x+4(-3+2x)) is 12x-1
What is the first derivative of (3x+4(-3+2x)) ?
The first derivative of (3x+4(-3+2x)) is 12x-1