What is the integral of cos^5(3x)sin(3x) ?

The integral of cos^5(3x)sin(3x) is -1/18 cos^6(3x)+C

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integral of cos^5(3x)sin(3x)

\int cos^{5} (3 x) sin (3 x) d x

- \frac{1}{18} cos^{6} (3 x) + C

Solution steps

\int cos^{5} (3 x) sin (3 x) d x

Apply u-substitution

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply the Power Rule

: \frac{5}{6} u^{\frac{6}{5}}

= - \frac{1}{15} \cdot \frac{5}{6} u^{\frac{6}{5}}

Substitute back

u = cos^{5} (3 x)

= - \frac{1}{15} \cdot \frac{5}{6} (cos^{5} (3 x))^{\frac{6}{5}}

Simplify

- \frac{1}{15} \cdot \frac{5}{6} (cos^{5} (3 x))^{\frac{6}{5}} : - \frac{1}{18} cos^{6} (3 x)

= - \frac{1}{18} cos^{6} (3 x)

Add a constant to the solution

= - \frac{1}{18} cos^{6} (3 x) + C

\frac{\partial}{\partial x} (\frac{4 x}{x ^{2} + y ^{2}})

x \to - 7 lim (2 x + 5)

\frac{\partial}{\partial x} (ln (2 x^{3} + 3 y^{2}))

\frac{5}{( 2 x - 3 ) ^{4}}

\frac{1 - x}{1 + x}

What is the integral of cos^5(3x)sin(3x) ?
The integral of cos^5(3x)sin(3x) is -1/18 cos^6(3x)+C