What is (\partial)/(\partial x)(800-0.001x^2-xy) ?

The answer to (\partial)/(\partial x)(800-0.001x^2-xy) is -0.002x-y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(800-0.001x^2-xy)

\frac{\partial}{\partial x} (800 - 0.001 x^{2} - x y)

- 0.002 x - y

Solution steps

\frac{\partial}{\partial x} (800 - 0.001 x^{2} - x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (800) - \frac{\partial}{\partial x} (0.001 x^{2}) - \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (800) = 0

\frac{\partial}{\partial x} (0.001 x^{2}) = 0.002 x

\frac{\partial}{\partial x} (x y) = y

= 0 - 0.002 x - y

Simplify

= - 0.002 x - y

x \cdot 3^{x}

\frac{3 s}{s ^{2} - 2 s + 2}

\int \frac{x}{( 4 + x y ) ^{2}} d y

\int cos^{5} (9 - 11 x) d x

\frac{d}{d x} (\frac{3 x - 4}{2 x - 8})

What is (\partial)/(\partial x)(800-0.001x^2-xy) ?
The answer to (\partial)/(\partial x)(800-0.001x^2-xy) is -0.002x-y