What is the integral of (e^{3.1})^2 ?

The integral of (e^{3.1})^2 is 492.74904…x+C

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integral of (e^{3.1})^2

\int (e^{3.1})^{2} d x

492.74904 \dots x + C

Solution steps

\int (e^{3.1})^{2} d x

Integral of a constant:

\int a d x = a x

= (e^{3.1})^{2} x

Simplify

(e^{3.1})^{2} x : 492.74904 \dots x

= 492.74904 \dots x

Add a constant to the solution

= 492.74904 \dots x + C

\frac{d}{d x} (cos (2 sin (x)))

x \to 2 lim (x^{2} + 2 x - 1)

\frac{d}{d x} (sin (\frac{π}{4} e^{2 x}))

\frac{d}{d x} (3 x^{2} (x^{3} + 1)^{7})

t^{2} y^{^{''}} - 3 t y^{^{'}} + 4 y = t^{2} \cdot ln (t)

What is the integral of (e^{3.1})^2 ?
The integral of (e^{3.1})^2 is 492.74904…x+C