What is (\partial)/(\partial v)(2vsin(u)) ?

The answer to (\partial)/(\partial v)(2vsin(u)) is 2sin(u)

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(\partial)/(\partial v)(2vsin(u))

\frac{\partial}{\partial v} (2 v sin (u))

2 sin (u)

Solution steps

\frac{\partial}{\partial v} (2 v sin (u))

Treat

u

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 sin (u) \frac{\partial}{\partial v} (v)

Apply the common derivative:

\frac{\partial}{\partial v} (v) = 1

= 2 sin (u) \cdot 1

Simplify

= 2 sin (u)

\frac{1}{s ^{2} - s}

x \to \frac{1}{5} lim (\frac{x}{10 x - 2})

\frac{d}{d x} ((cos (x))^{3})

x^{^{'}} + \frac{2}{1 + t} x = \frac{e ^{t}}{1 + t}

\int_{- 1}^{1} 3 x^{2} x^{3} + 5 d x

What is (\partial)/(\partial v)(2vsin(u)) ?
The answer to (\partial)/(\partial v)(2vsin(u)) is 2sin(u)