What is the derivative of f(x)=tan(x^2+3x-4) ?

The derivative of f(x)=tan(x^2+3x-4) is sec^2(x^2+3x-4)(2x+3)

What is the first derivative of f(x)=tan(x^2+3x-4) ?

The first derivative of f(x)=tan(x^2+3x-4) is sec^2(x^2+3x-4)(2x+3)

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derivative of

f (x) = tan (x^{2} + 3 x - 4)

sec^{2} (x^{2} + 3 x - 4) (2 x + 3)

Solution steps

\frac{d}{d x} (tan (x^{2} + 3 x - 4))

Apply the chain rule:

sec^{2} (x^{2} + 3 x - 4) \frac{d}{d x} (x^{2} + 3 x - 4)

= sec^{2} (x^{2} + 3 x - 4) \frac{d}{d x} (x^{2} + 3 x - 4)

\frac{d}{d x} (x^{2} + 3 x - 4) = 2 x + 3

= sec^{2} (x^{2} + 3 x - 4) (2 x + 3)

\int \frac{cos ( u )}{u} d u

\frac{\partial}{\partial y} ((x - y)^{10})

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f (x) = x^{7}

2 t sin (t)

What is the derivative of f(x)=tan(x^2+3x-4) ?
The derivative of f(x)=tan(x^2+3x-4) is sec^2(x^2+3x-4)(2x+3)
What is the first derivative of f(x)=tan(x^2+3x-4) ?
The first derivative of f(x)=tan(x^2+3x-4) is sec^2(x^2+3x-4)(2x+3)