What is laplacetransform 13e^{4t}e^2 ?

The answer to laplacetransform 13e^{4t}e^2 is (13e^2)/(s-4)

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laplacetransform 13e^{4t}e^2

laplace transform

13 e^{4 t} e^{2}

\frac{13 e ^{2}}{s - 4}

Solution steps

L {13 e^{2} e^{4 t}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 13 e^{2} L {e^{4 t}}

L {e^{4 t}} : \frac{1}{s - 4}

= 13 e^{2} \frac{1}{s - 4}

Refine

13 e^{2} \frac{1}{s - 4} : \frac{13 e ^{2}}{s - 4}

= \frac{13 e ^{2}}{s - 4}

\frac{d}{d x} (\frac{x - 3}{x + 4})

\int_{1}^{e} ln (3 x) d x

\frac{d}{d x} (tan^{3} (x) + tan (x^{3}))

\frac{\partial}{\partial x} (- 2 x e^{- x y})

\frac{d y}{d x} - 2 x y = x

What is laplacetransform 13e^{4t}e^2 ?
The answer to laplacetransform 13e^{4t}e^2 is (13e^2)/(s-4)