What is the solution for (dy)/(dx)+y-cos(x)=0 ?

The solution for (dy)/(dx)+y-cos(x)=0 is y=(sin(x))/2+(cos(x))/2+(c_{1})/(e^x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)+y-cos(x)=0

\frac{d y}{d x} + y - cos (x) = 0

y = \frac{sin ( x )}{2} + \frac{cos ( x )}{2} + \frac{c _{1}}{e ^{x}}

Solution steps

\frac{d y}{d x} + y - cos (x) = 0

Solve linear ODE:

y = \frac{sin ( x )}{2} + \frac{cos ( x )}{2} + \frac{c _{1}}{e ^{x}}

y = \frac{sin ( x )}{2} + \frac{cos ( x )}{2} + \frac{c _{1}}{e ^{x}}

f (x) = x^{3} (x - 1)^{2}

- 10 ln (x e^{x^{8}})

n = 1 \sum \infty in (\frac{1}{n})

\frac{d}{d x} (\frac{3 x - 2}{2 x + 3})

g (t) = t^{7} cos (t)

What is the solution for (dy)/(dx)+y-cos(x)=0 ?
The solution for (dy)/(dx)+y-cos(x)=0 is y=(sin(x))/2+(cos(x))/2+(c_{1})/(e^x)