What is the derivative of-1/(cos(x)) ?

The derivative of-1/(cos(x)) is -sec(x)tan(x)

What is the first derivative of-1/(cos(x)) ?

The first derivative of-1/(cos(x)) is -sec(x)tan(x)

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\frac{d}{d x} (- \frac{1}{cos ( x )})

- sec (x) tan (x)

Solution steps

\frac{d}{d x} (- \frac{1}{cos ( x )})

Simplify

- \frac{1}{cos ( x )} : - sec (x)

= \frac{d}{d x} (- sec (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (sec (x))

Apply the common derivative:

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

= - sec (x) tan (x)

n = 0 \sum \infty cos (\frac{π}{2})

f (x) = 4 x^{2} - 5 x, (- 1, 9)

n = 1 \sum \infty \frac{3 ^{n}}{n ^{3}}

\int_{0}^{1} 7 x x^{2} + 9 d x

\int \frac{x ^{2} + 1}{( x - 7 ) ( x - 6 )} d x

What is the derivative of-1/(cos(x)) ?
The derivative of-1/(cos(x)) is -sec(x)tan(x)
What is the first derivative of-1/(cos(x)) ?
The first derivative of-1/(cos(x)) is -sec(x)tan(x)