What is inverse oflaplace (0.625)/(s+4) ?

The answer to inverse oflaplace (0.625)/(s+4) is 0.625e^{-4t}

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inverse oflaplace (0.625)/(s+4)

inverse laplace

\frac{0.625}{s + 4}

0.625 e^{- 4 t}

Solution steps

L^{- 1} {\frac{0.625}{s + 4}}

= L^{- 1} {0.625 \cdot \frac{1}{s + 4}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 0.625 L^{- 1} {\frac{1}{s + 4}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s + 4}} = e^{- 4 t}

= 0.625 e^{- 4 t}

x \to 0 lim (\frac{x ^{2} + 2 x - 99}{x})

\int \frac{2 x}{1 + x ^{4}} d x

y = (x + 3)^{3}

x^{2} y^{^{''}} + x y^{^{'}} - y = \frac{ln ( x )}{x ^{2}}

\frac{x + 1}{x ^{2} + 1}

What is inverse oflaplace (0.625)/(s+4) ?
The answer to inverse oflaplace (0.625)/(s+4) is 0.625e^{-4t}