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Popular >

integral of (x^3-9x)

Solution

\int (x^{3} - 9 x) d x

Solution

\frac{x ^{4}}{4} - \frac{9 x ^{2}}{2} + C

Solution steps

\int x^{3} - 9 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{3} d x - \int 9 x d x

\int x^{3} d x = \frac{x ^{4}}{4}

\int 9 x d x = \frac{9 x ^{2}}{2}

= \frac{x ^{4}}{4} - \frac{9 x ^{2}}{2}

Add a constant to the solution

= \frac{x ^{4}}{4} - \frac{9 x ^{2}}{2} + C

Popular Examples

integral of 4cos^3(x)

\int 4 cos^{3} (x) d x

derivative of-6b^2x(a^2-b^2x^2^2)

\frac{d}{d x} (- 6 b^{2} x (a^{2} - b^{2} x^{2})^{2})

derivative of (x+1)^3 derivative of

(x + 1)^{3}

inverse oflaplace t inverse laplace

t

integral from 0 to 2 of (x^3)/(x^2+1)

\int_{0}^{2} \frac{x ^{3}}{x ^{2} + 1} d x

Frequently Asked Questions (FAQ)

What is the integral of (x^3-9x) ?
The integral of (x^3-9x) is (x^4)/4-(9x^2)/2+C