What is the derivative of 1/(\sqrt[5]{x}) ?

The derivative of 1/(\sqrt[5]{x}) is -1/(5x^{6/5)}

What is the first derivative of 1/(\sqrt[5]{x}) ?

The first derivative of 1/(\sqrt[5]{x}) is -1/(5x^{6/5)}

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- \frac{1}{5 x ^{\frac{6}{5}}}

Solution steps

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} (x^{- \frac{1}{5}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{1}{5} x^{- \frac{1}{5} - 1}

Simplify

- \frac{1}{5} x^{- \frac{1}{5} - 1} : - \frac{1}{5 x ^{\frac{6}{5}}}

= - \frac{1}{5 x ^{\frac{6}{5}}}

x \to - 2 lim (3 x^{2} + 4 x - 2)

\frac{d y}{d x} = e^{4 x + 3 y}

y = 30 e^{- 0.0000323 h}

\frac{d}{d x} (x - x)

\frac{d}{d x} ((ln (x))^{c o s (x)})

What is the derivative of 1/(\sqrt[5]{x}) ?
The derivative of 1/(\sqrt[5]{x}) is -1/(5x^{6/5)}
What is the first derivative of 1/(\sqrt[5]{x}) ?
The first derivative of 1/(\sqrt[5]{x}) is -1/(5x^{6/5)}