What is (\partial)/(\partial z)(3yz^2) ?

The answer to (\partial)/(\partial z)(3yz^2) is 6yz

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(\partial)/(\partial z)(3yz^2)

\frac{\partial}{\partial z} (3 y z^{2})

6 yz

Solution steps

\frac{\partial}{\partial z} (3 y z^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 y \frac{\partial}{\partial z} (z^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 y \cdot 2 z^{2 - 1}

Simplify

= 6 yz

\int_{1}^{10} 5 x - 1 d x

\frac{d}{d x} (x^{- 3} y^{- 4})

n \to \infty lim (n^{0})

f (x) = 3^{(x^{5})}

y^{^{'}} + b y = 0

What is (\partial)/(\partial z)(3yz^2) ?
The answer to (\partial)/(\partial z)(3yz^2) is 6yz