What is the derivative of-2sin(2x+1/x) ?

The derivative of-2sin(2x+1/x) is -4cos(2x)-1/(x^2)

What is the first derivative of-2sin(2x+1/x) ?

The first derivative of-2sin(2x+1/x) is -4cos(2x)-1/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (- 2 sin (2 x) + \frac{1}{x})

- 4 cos (2 x) - \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (- 2 sin (2 x) + \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 sin (2 x)) + \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (2 sin (2 x)) = 4 cos (2 x)

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= - 4 cos (2 x) - \frac{1}{x ^{2}}

y = x - x^{3}

\int e^{- 2 \cdot π \cdot x} \cdot cos (π \cdot x) d x

n = 1 \sum \infty \frac{1}{4 n ^{4}}

\int \frac{x ^{2} - 5}{( x + 1 ) ^{3}} d x

\int_{0}^{π} 20 sin^{4} (x) d x

What is the derivative of-2sin(2x+1/x) ?
The derivative of-2sin(2x+1/x) is -4cos(2x)-1/(x^2)
What is the first derivative of-2sin(2x+1/x) ?
The first derivative of-2sin(2x+1/x) is -4cos(2x)-1/(x^2)