What is the limit as x approaches 0-of 2x-8x^2 ?

The limit as x approaches 0-of 2x-8x^2 is 0

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limit as x approaches 0-of 2x-8x^2

x \to 0 - lim (2 x - 8 x^{2})

0

Solution steps

x \to 0 - lim (2 x - 8 x^{2})

Plug in the value

x = 0

= 2 \cdot 0 - 8 \cdot 0^{2}

Simplify

= 0

y^{^{''}} - 2 y + y = \frac{e ^{x}}{1 + x ^{2}}

x \to 1 + lim (3 x - 3 + 2)

y^{^{'}} sin (x) + y cos (x) = 0, y (\frac{π}{4}) = 1

\frac{d}{d x} (x^{4} tan (x))

x \to 0 + lim ((\frac{1}{x})^{l n (x)})

What is the limit as x approaches 0-of 2x-8x^2 ?
The limit as x approaches 0-of 2x-8x^2 is 0