What is the derivative of (3/4 x)^3 ?

The derivative of (3/4 x)^3 is (81x^2)/(64)

What is the first derivative of (3/4 x)^3 ?

The first derivative of (3/4 x)^3 is (81x^2)/(64)

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derivative of

(\frac{3}{4} x)^{3}

\frac{81 x ^{2}}{64}

Solution steps

\frac{d}{d x} ((\frac{3}{4} x)^{3})

Apply the chain rule:

3 (\frac{3}{4} x)^{2} \frac{d}{d x} (\frac{3}{4} x)

= 3 (\frac{3}{4} x)^{2} \frac{d}{d x} (\frac{3}{4} x)

\frac{d}{d x} (\frac{3}{4} x) = \frac{3}{4}

= 3 (\frac{3}{4} x)^{2} \frac{3}{4}

Simplify

3 (\frac{3}{4} x)^{2} \frac{3}{4} : \frac{81 x ^{2}}{64}

= \frac{81 x ^{2}}{64}

\int \frac{49}{x ^{3} - 7 x ^{2}} d x

\frac{d y}{d x} + 12 y = 5

\frac{d}{d x} ((cos (x)) x)

x^{2} \frac{d y}{d x} = y - x y, y (- 1) = - 2

f (x) = ln (x^{3} + 10)

What is the derivative of (3/4 x)^3 ?
The derivative of (3/4 x)^3 is (81x^2)/(64)
What is the first derivative of (3/4 x)^3 ?
The first derivative of (3/4 x)^3 is (81x^2)/(64)