What is the integral of (x^3)/(sqrt(49+x^2)) ?

The integral of (x^3)/(sqrt(49+x^2)) is 1/3 (49+x^2)^{3/2}-49sqrt(49+x^2)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x^3)/(sqrt(49+x^2))

\int \frac{x ^{3}}{49 + x ^{2}} d x

\frac{1}{3} (49 + x^{2})^{\frac{3}{2}} - 49 49 + x^{2} + C

Solution steps

\int \frac{x ^{3}}{49 + x ^{2}} d x

Apply u-substitution

: \int u^{2} - 49 d u

= \int u^{2} - 49 d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int u^{2} d u - \int 49 d u

\int u^{2} d u = \frac{u ^{3}}{3}

\int 49 d u = 49 u

= \frac{u ^{3}}{3} - 49 u

Substitute back

u = 49 + x^{2}

= \frac{( 49 + x ^{2} ) ^{3}}{3} - 49 49 + x^{2}

Simplify

\frac{( 49 + x ^{2} ) ^{3}}{3} - 49 49 + x^{2} : \frac{1}{3} (49 + x^{2})^{\frac{3}{2}} - 49 49 + x^{2}

= \frac{1}{3} (49 + x^{2})^{\frac{3}{2}} - 49 49 + x^{2}

Add a constant to the solution

= \frac{1}{3} (49 + x^{2})^{\frac{3}{2}} - 49 49 + x^{2} + C

f (x) = arcsec (6 x)

\int \frac{3}{1 - 2 x} d x

e^{x^{5}}, 0

x \to 1 lim (x^{2} - 4)

\int \frac{3 e ^{2 x}}{e ^{2 x} + 9 e ^{x} + 18} d x

What is the integral of (x^3)/(sqrt(49+x^2)) ?
The integral of (x^3)/(sqrt(49+x^2)) is 1/3 (49+x^2)^{3/2}-49sqrt(49+x^2)+C