What is the d/(dθ)(-6sin(θ)) ?

The d/(dθ)(-6sin(θ)) is -6cos(θ)

What is the first d/(dθ)(-6sin(θ)) ?

The first d/(dθ)(-6sin(θ)) is -6cos(θ)

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\frac{d}{d θ} (- 6 sin (θ))

- 6 cos (θ)

Solution steps

\frac{d}{d θ} (- 6 sin (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 6 \frac{d}{d θ} (sin (θ))

Apply the common derivative:

\frac{d}{d θ} (sin (θ)) = cos (θ)

= - 6 cos (θ)

\frac{d}{d x} (- \frac{1}{( 2 x + 8 ) ^{\frac{3}{2}}})

\int + \frac{1}{x ^{2}} d x

\frac{d}{d x} (\frac{x}{x + 5})

\frac{d}{d t} (cos (2 t))

y^{^{''}} - 2 y^{^{'}} + y = x^{2} - 1