What is the limit as x approaches 0 of 1/x+1/(x^2) ?

The limit as x approaches 0 of 1/x+1/(x^2) is infinity

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limit as x approaches 0 of 1/x+1/(x^2)

x \to 0 lim (\frac{1}{x} + \frac{1}{x ^{2}})

\infty

Solution steps

x \to 0 lim (\frac{1}{x} + \frac{1}{x ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 0 - lim (\frac{1}{x} + \frac{1}{x ^{2}}) = \infty

x \to 0 + lim (\frac{1}{x} + \frac{1}{x ^{2}}) = \infty

= \infty

n = 1 \sum \infty (2 n)!

n \to 0 lim (ln (n))

\int \frac{x}{x ^{2} + 8} d x

8 x^{\frac{3}{2}} + 6 x^{\frac{1}{2}} + 4^{- \frac{1}{2}}

What is the limit as x approaches 0 of 1/x+1/(x^2) ?
The limit as x approaches 0 of 1/x+1/(x^2) is infinity